Advanced Search

Open PHP5 Object, No need to declare variable name first

/ Published in: PHP
Save to your folder(s)
I use this object verry often, so that I only need to pass one object as parameter on any function. No need to wory when we refactore the function
Usage:
$var = new open();
$var->url = 'http://www.world.com';
$var->title = 'Testing Site';

echo some_function($var);

Expand | Embed | Plain Text

Copy this code and paste it in your HTML 
  1. //PHP5 only//
  2.  
  3. class open
  4. {
  5.    var $____x = array();
  6.    function __construct($a = array())
  7.    {
  8.       $this->fromArray($a);
  9.    }
  10.  
  11.    function __set($name,$val)
  12.    {
  13.       $this->____x[$name] = $val;
  14.    }
  15.  
  16.    function __get($name)
  17.    {
  18.        if(isset($this->____x[$name])) return $this->____x[$name];
  19.    }
  20.  
  21.    function __isset($name)
  22.    {
  23.       return isset($this->____x[$name]);
  24.    }
  25.  
  26.    function toArray()
  27.    {
  28.       return $this->____x;
  29.    }
  30.  
  31.    function fromArray($a = array())
  32.    {
  33.       if(count($a)>0) foreach($a as $k => $v) $this->____x[$k] = $v;
  34.    }
  35.  
  36. }

Report this snippet


Comments

RSS Icon Subscribe to comments

You need to login to post a comment.