Advanced Search

Posted By

mateom11 on 01/19/15

Tagged

Versions (?)

Last Edited at 01/19/15 05:28am

Statistics

Viewed 544 times
Favorited by 0 user(s)

Related snippets

897
binarno_stablo_polje.h

Binarno_stablo_polje.h

/ Published in: C++
Save to your folder(s)
Binarno_stablo_polje

Expand | Embed | Plain Text

Copy this code and paste it in your HTML 
  1. #include <iostream>
  2.  
  3. using namespace std;
  4.  
  5. struct element {
  6. 	int label;
  7. 	bool used;
  8. };
  9.  
  10. struct bt {
  11. 	struct element polje[1000];
  12. };
  13.  
  14. typedef struct bt* btree;
  15. typedef int node;
  16.  
  17.  
  18.  
  19. void InitB(int x,btree T){
  20. 	for(int i=0;i<1000;i++) T->polje[i].used=false;
  21. 	T->polje[1].label = x;
  22. 	T->polje[1].used=true;
  23. }
  24.  
  25. int LabelB(node n,btree T){
  26. 	return T->polje[n].label;
  27. }
  28.  
  29. void ChangeLabelB(int x,node n,btree T){
  30. 	T->polje[n].label=x;
  31. }
  32. node RootB(btree T){
  33.  
  34. 	if (T->polje[1].used) return 1;
  35. 	else return -1;
  36. }
  37.  
  38. node ParentB(node n,btree T){
  39. 	if(n==1) return -1;	
  40. 	return n/2;
  41. }                                                               
  42.  
  43. void CreateLeftB(node x,node n,btree T){
  44. 	if (!T->polje[n*2].used && T->polje[n].used){
  45.  		T->polje[n*2].used=true;
  46. 		T->polje[n*2].label=x; 	
  47. 	 }	
  48.  	else cout<<"Greska, cvor se nemoze kreirati!"<<endl;
  49. }
  50.  
  51. void CreateRightB(int x,node n,btree T){
  52.  if (!T->polje[n*2+1].used && T->polje[n].used){
  53.  	T->polje[n*2+1].used=true;
  54. 	T->polje[n*2+1].label=x; 	
  55.  }	
  56.  else cout<<"Greska, cvor se nemoze kreirati!"<<endl;
  57. }
  58.  
  59. node LeftChildB(node n,btree T){
  60. 	if(T->polje[n*2].used) return n*2;
  61. 	else return -1;
  62. }
  63. node RightChildB(node n,btree T){
  64. 	if(T->polje[n*2+1].used) return n*2+1;
  65. 	else return -1;
  66. }
  67.  
  68. void DeleteB(node n,btree T){
  69. 	if(LeftChildB(n,T)!=-1) DeleteB(LeftChildB(n,T),T);
  70.     if(RightChildB(n,T)!=-1) DeleteB(RightChildB(n,T),T);
  71.     T->polje[n].used = false;
  72. }
  73.  
  74. bool ExistRightChild(node n,btree T){
  75. 	if(T->polje[2*n+1].used) return true;
  76. 	return false;
  77. }
  78.  
  79. bool ExistLeftChild(node n,btree T){
  80. 	if(T->polje[2*n].used) return true;
  81. 	return false;
  82. }

Report this snippet


Comments

RSS Icon Subscribe to comments

You need to login to post a comment.