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AOT_code on 01/12/14

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Last Edited at 01/12/14 01:22pm

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binarno_stabo_polje.h

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Implementacija binarnog stabla koristeći se poljem.

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  1. struct arr_element{
  2. 	int label, used;
  3. };
  4.  
  5. struct arr_tree{
  6. 	arr_element array[10000];
  7. };
  8.  
  9. arr_tree* InitB(int x, arr_tree* T){
  10. 	T = new arr_tree;
  11. 	for(int i=0; i<10000; i++) T->array[i].used = 0;
  12. 	T->array[1].label = x;
  13. 	T->array[1].used = 1;
  14. 	return T;
  15. }
  16.  
  17. int RootB(arr_tree* T){
  18. 	return T->array[1].label;
  19. }
  20.  
  21. int LabelB(int n, arr_tree* T){
  22. 	return T->array[n].label;
  23. }
  24.  
  25. int ChangeLabelB(int x, int n, arr_tree* T){
  26. 	return T->array[n].label = x;
  27. }
  28.  
  29. int ParentB(int n,arr_tree *T){
  30. 	if(T->array[1].label==n) return -1;
  31. 	if(n%2) return n/2+1;
  32. 	else return n/2;
  33. }
  34.  
  35. int LeftChildB(int n, arr_tree* T){
  36. 	if(!(T->array[2*n].used)) return -1;
  37. 	else return 2*n;
  38. } 
  39.  
  40. int RightChildB(int n, arr_tree* T){
  41. 	if(!(T->array[2*n+1].used)) return -1;
  42. 	else return 2*n+1;
  43. }
  44.  
  45. void CreateLeftB(int x, int n, arr_tree* T){
  46. 	if(T->array[2*n].used) cout << "Pozicija je zauzeta!" << endl;
  47. 	else{
  48. 		T->array[2*n].label = x;
  49. 		T->array[2*n].used = 1;
  50. 	}
  51. }
  52.  
  53. void CreateRightB(int x, int n, arr_tree* T){
  54. 	if(T->array[2*n+1].used) cout << "Pozicija je zauzeta!" << endl;
  55. 	else{
  56. 		T->array[2*n+1].label = x;
  57. 		T->array[2*n+1].used = 1;
  58. 	}
  59. }
  60.  
  61. bool DeleteB(int n, arr_tree* T){
  62. 	if(LeftChildB(n,T) != -1) DeleteB(LeftChildB(n,T),T);
  63. 	if(RightChildB(n,T) != -1) DeleteB(RightChildB(n,T),T);
  64. 	T->array[n].used = 0;
  65. }

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