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binaryadder on 02/03/12

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Last Edited at 02/03/12 05:55am

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Vector Operations

/ Published in: C

Output:

Vector A:
x: 1.000000
y: 2.000000
z: 3.000000

Vector B:
x: 2.000000
y: 3.000000
z: 4.000000

Adding A and B gives the vector:
x: 3.000000
y: 5.000000
z: 7.000000

Dot product of A and B is 20.000000.

Cross product of A and B gives the vector:
x: -1.000000
y: 2.000000
z: -1.000000

Multiplying A by the scalar quantity 5.0 gives the vector:
x: 5.000000
y: 10.000000
z: 15.000000

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#include <stdio.h>

struct vector {
	float x;
	float y;
	float z;
};

void printVec(struct vector vec){
	printf("x: %f\ny: %f\nz: %f\n\n", vec.x, vec.y, vec.z);
}

void addVec(struct vector op1, struct vector op2, struct vector *result){
	result->x = op1.x + op2.x;
	result->y = op1.y + op2.y;
	result->z = op1.z + op2.z;
}

void initVec(float x, float y, float z, struct vector *vec){
	vec->x = x; vec->y = y; vec->z = z;
}

void multVec(float scalar, struct vector *vec){
	vec->x *= scalar; vec->y *= scalar; vec->z *= scalar;
}

float dotVec(struct vector A, struct vector B){
	return ((A.x * B.x) + (A.y * B.y) + (A.z * B.z));
}

void crossVec(struct vector A, struct vector B, struct vector *C){
	C->x = ((A.y * B.z) - (A.z * B.y));
	C->y = ((A.z * B.x) - (A.x * B.z));
	C->z = ((A.x * B.y) - (A.y * B.x));
}

void main(){
	struct vector A;
	struct vector B;
	struct vector C;
	initVec(1.0, 2.0, 3.0, &A);
	initVec(2.0, 3.0, 4.0, &B);
	printf("Vector A:\n");
	printVec(A);
	printf("Vector B:\n");
	printVec(B);
	printf("Adding A and B gives the vector:\n");
	addVec(A, B, &C);
	printVec(C);
        printf("Dot product of A and B is %f.\n\n", dotVec(A, B));
	printf("Cross product of A and B gives the vector:\n");
	crossVec(A, B, &C);
	printVec(C);
	printf("Multiplying A by the scalar quantity 5.0 gives the vector:\n");
	multVec(5.0, &A);
	printVec(A);
}

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