/ Published in: Python
converts numbers to their english style
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# this is program to convert mathematical number to alphabetical numbers # this can easily change to any language (if possible) words by modifying the lists below def translate(d): import copy lst1=['one ','two ','three ','for ','five ','six ','seven ','eight','nine','ten','eleven','twelve ','thirteen ','fourteen ','fifteen ','sixteen ','seventeen ','eighteen ','nineteen '] lst2=['twenty ','thity ','forty ','fifty ','sixty ','seventy ','eighty ','ninety '] lst3=['one hundred ','two hundred ','three hundred ','for hundred ','five hundred ','sixe hundred ','seven hundred ','eight hundred ','nine hundred '] lst4=['thousand ','million ','billion ','trillion '] s='' t=int();y=int(d) if d==0: return 'zero' while d!=0: #--------- main LOOP if d<20: #------if number < 20 s=s+lst1[d-1]+' ' return s if d>=100 and d<1000: #------if 100<number < 1000 s=s+lst3[d/100-1] if d%100==0: return s while(d>99): d-=100 if d>19 and d<100: #------if number < 100 y=d%10 t=d-(d%10) s=s+lst2[(t/10)-2]+' ' if y!=0: s=s+lst1[y-1]+' ' return s if d>1000000000000: # ---------------if number < 1000 trilions first=str() first=translate(d/1000000000000) s+=first+' '+lst4[3]+' ' if d%1000000000000==0: return s while d>1000000000000: d-=1000000000000 if d>1000000000: #------if number < one triliion first=str() first=translate(d/1000000000) s+=first+' '+lst4[2]+' ' if d%1000000000==0: return s while d>1000000000: d-=1000000000 if d>=1000000: #------if number < one bilion first=str() first=translate(d/1000000) s=s+first+' '+lst4[1]+' ' if d%1000000==0: return s while (d>1000000): d-=1000000 if d>=1000: #------if number < 1000 first=str() first=translate(d/1000) s=s+first+' '+lst4[0]+' ' if d%1000==0: return s while (d>1000): d-=1000 # -------------------------------- if __name__=="__main__": d=raw_input('enter number or q to quit: ') if d=='q': exit() d=int(d) print translate(d) print '\n'