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AJAX MySQL Query

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  1. function sendProject(){
  2.  
  3. 	if (window.XMLHttpRequest)
  4.   	{// code for IE7+, Firefox, Chrome, Opera, Safari
  5.  		xmlhttp=new XMLHttpRequest();
  6.   	}else{// code for IE6, IE5
  7.   		xmlhttp=new ActiveXObject("Microsoft.XMLHTTP");
  8.   	}
  9.  
  10. 	xmlhttp.onreadystatechange=function()
  11.   	{
  12.   		if (xmlhttp.readyState==4 && xmlhttp.status==200)
  13.     	{
  14.     		document.getElementById('files').style.display = "inline";
  15. 			document.getElementById('project').style.display = "none";
  16. 			pid = xmlhttp.responseText;
  17.     	}
  18. 	}
  19. 	var title=encodeURIComponent(document.getElementById("p_title").value);
  20. 	var description=encodeURIComponent(document.getElementById("p_description").value);
  21. 	var featured=encodeURIComponent(document.getElementById("p_featured").value);
  22. 	var parameters= "title="+title+"&description="+description+"&featured="+featured;
  23. 	xmlhttp.open("POST", "../scr/addProject.php", true);
  24. 	xmlhttp.setRequestHeader("Content-type", "application/x-www-form-urlencoded");
  25. 	xmlhttp.send(parameters);
  26. }

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