Advanced Search

Posted By

drmarinko on 01/06/11

Tagged

Versions (?)

Last Edited at 01/06/11 09:11am

Statistics

Viewed 542 times
Favorited by 0 user(s)

Related snippets

614
bstablo_polje.h
570
bstablo_polje.h
555
bstablo_polje.h
554
zaglavlje bstablo_polje.h
557
bstablo_polje.h
568
bstablo_polje.h - marmomcil
565
bstablo_polje.h
590
bstablo_polje.h
496
b_stablo_polje.h

bstablo_polje.h

/ Published in: C++
Save to your folder(s)

Expand | Embed | Plain Text

Copy this code and paste it in your HTML 
  1. struct element
  2. {
  3.        labeltype label;
  4.        int used;
  5. };
  6.  
  7. typedef struct bt
  8. {
  9.        element elements[10000];
  10. } *btree;
  11.  
  12. typedef int node;
  13.  
  14. node RootB(btree b_stablo)
  15. {
  16. 	if (b_stablo->elements[1].used == 1) 
  17. 		return 1;
  18. 	else
  19. 		return 0;
  20. }
  21.  
  22. void InitB(labeltype v, btree b_stablo)
  23. {
  24. 	for (int i = 0; i<10000; i++) 
  25. 		b_stablo->elements[i].used = 0; 
  26. 	b_stablo->elements[1].label = v; 
  27. 	b_stablo->elements[1].used = 1; 
  28. }
  29.  
  30. labeltype LabelB(node n, btree b_stablo)
  31. {
  32. 	return b_stablo->elements[n].label; 
  33. }
  34.  
  35. void ChangeLabelB(labeltype v, node n, btree b_stablo)
  36. {
  37. 	b_stablo->elements[n].label = v; 
  38. }
  39.  
  40. int ExistsLeftChild(node n, btree b_stablo)
  41. {
  42. 	if (b_stablo->elements[2*n].used == 1) 
  43. 		return 1;
  44. 	else
  45. 		return 0;
  46. }
  47.  
  48. int ExistsRightChild(node n, btree b_stablo)
  49. {
  50. 	if (b_stablo->elements[(2*n)+1].used == 1) 
  51. 		return 1;
  52. 	else
  53. 		return 0;
  54. }
  55.  
  56. void CreateLeftB(labeltype v, node n, btree b_stablo)
  57. {
  58. 	if (ExistsLeftChild(n, b_stablo)) 
  59. 		cout << "Lijevo dijete vec postoji\n";
  60. 	else 
  61. 	{
  62. 		b_stablo->elements[2*n].used = 1; 
  63. 		b_stablo->elements[2*n].label = v; 
  64. 	}
  65. }
  66.  
  67. void CreateRightB(labeltype v, node n, btree b_stablo)
  68. {
  69. 	if (ExistsRightChild(n, b_stablo))
  70. 		cout << "Desno dijete vec postoji\n";
  71. 	else 
  72. 	{
  73. 		b_stablo->elements[(2*n)+1].used = 1; 
  74. 		b_stablo->elements[(2*n)+1].label = v; 
  75. 	}
  76. }
  77.  
  78. node LeftChildB(node n, btree b_stablo)
  79. {
  80. 	if (ExistsLeftChild(n, b_stablo)) 
  81. 		return 2*n; 
  82. 	else
  83. 		return 0;
  84. }
  85.  
  86. node RightChildB(node n, btree b_stablo)
  87. {
  88. 	if (ExistsRightChild(n, b_stablo)) 
  89. 		return (2*n)+1; 
  90. 	else
  91. 		return 0;
  92. }
  93.  
  94. node ParentB(node n, btree b_stablo)
  95. {
  96.      if(n == 1) 
  97. 		 return 0;
  98. 	 if(n%2) 
  99. 		 n--; 
  100.      return n/2; 
  101. }
  102.  
  103.  
  104. void DeleteB(node n, btree b_stablo)
  105. {
  106. 	if (ExistsLeftChild(n, b_stablo)) 
  107. 		DeleteB(LeftChildB(n, b_stablo), b_stablo); 
  108. 	if (ExistsRightChild(n, b_stablo)) 
  109. 		DeleteB(RightChildB(n, b_stablo), b_stablo);
  110. 	b_stablo->elements[n].used = 0; 
  111. }

Report this snippet


Comments

RSS Icon Subscribe to comments

You need to login to post a comment.