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Super fast FileServlet

/ Published in: Java
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  1. private void output(HttpServletResponse response, String filePathAndFileName, String mimeType)
  2.       throws IOException {
  3.  
  4.     File file = new File(filePathAndFileName);
  5.  
  6.     // set response headers
  7.     response.setContentType((mimeType != null) ? mimeType : "application/octet-stream");
  8.     response.setContentLength((int) file.length());
  9.  
  10.  
  11.  
  12.     // read and write file
  13.     ServletOutputStream op = response.getOutputStream();
  14.     // 128 KB buffer
  15.     int bufferSize = 131072;
  16.     FileInputStream fileInputStream = new FileInputStream(file);
  17.     FileChannel fileChannel = fileInputStream.getChannel();
  18.     // 6x128 KB = 768KB byte buffer
  19.     ByteBuffer bb = ByteBuffer.allocateDirect(786432);
  20.     byte[] barray = new byte[bufferSize];
  21.     int nRead, nGet;
  22.  
  23.     try {
  24.       while ((nRead = fileChannel.read(bb)) != -1) {
  25.         if (nRead == 0)
  26.           continue;
  27.         bb.position(0);
  28.         bb.limit(nRead);
  29.         while (bb.hasRemaining()) {
  30.           nGet = Math.min(bb.remaining(), bufferSize);
  31.           // read bytes from disk
  32.           bb.get(barray, 0, nGet);
  33.           // write bytes to output
  34.           op.write(barray);
  35.         }
  36.         bb.clear();
  37.       }
  38.     } catch (IOException e) {
  39.       e.printStackTrace();
  40.     } finally {
  41.       bb.clear();
  42.       fileChannel.close();
  43.       fileInputStream.close();
  44.     }
  45.   }

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