select count distinct

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  1. SELECT DISTINCT pt_services.service_bezeichnungen, pt_class_services.class_services_name, COUNT(*) AS total
  2. FROM service
  3. INNER JOIN pt_services
  4. ON service.id_pt_service = pt_services.id_pt_service
  5. INNER JOIN pt_class_services
  6. ON service.id_class_services = pt_class_services.id_class_services
  7. GROUP BY pt_services.id_pt_service, pt_class_services.id_class_services;

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