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<p>this example checks that when the context switch occurs in the O'Caml runtime.
compile it with:</p>
<ol>
<li>ocamlc -vmthread -I +threads -I unix unix.cmxa threads.cmxa filename.ml</li>
<li>ocamlc -thread -I +threads -I unix unix.cmxa threads.cmxa filename.ml</li>
<li>ocamlopt -thread -I +threads -I unix unix.cmxa threads.cmxa filename.ml</li>
</ol>
<p>both 1. and 2. terminates, while 3. not (on my OCaml 3.11.1, on Mac OS X).</p>
<p><strong>See also:</strong><a href="http://snipplr.com/view/19509/">http://snipplr.com/view/19509/</a></p>
compile it with:</p>
<ol>
<li>ocamlc -vmthread -I +threads -I unix unix.cmxa threads.cmxa filename.ml</li>
<li>ocamlc -thread -I +threads -I unix unix.cmxa threads.cmxa filename.ml</li>
<li>ocamlopt -thread -I +threads -I unix unix.cmxa threads.cmxa filename.ml</li>
</ol>
<p>both 1. and 2. terminates, while 3. not (on my OCaml 3.11.1, on Mac OS X).</p>
<p><strong>See also:</strong><a href="http://snipplr.com/view/19509/">http://snipplr.com/view/19509/</a></p>
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let allocation _ = ignore (String.create 100000) let r = ref false;; let rec forever x = allocation (); r:=true; forever x;; let rec wait _ = if !r then print_string "end.\n" else (allocation (); wait ()) ;; Thread.create (fun _ -> forever ()) ();; wait ();; (* blocks forever if we comment out both occurrence of `allocation' *)