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Ajax simple call

/ Published in: JavaScript
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  1. function ajax(url, fn, async)
  2. {
  3.     var xmlhttp = new XMLHttpRequest();
  4.  
  5.     if ( async )
  6.     {
  7.         xmlhttp.onreadystatechange = function()
  8.         {
  9.             if ( xmlhttp.readyState == 4 && xmlhttp.status == 200 )
  10.             {
  11.                 fn(xmlhttp);
  12.             }
  13.         }
  14.     }
  15.     xmlhttp.open("GET", url, async);
  16.     xmlhttp.send(null);
  17.  
  18.     if ( !async )
  19.     {
  20.         fn(xmlhttp);
  21.     }
  22. }

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