Revision: 22631
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at January 17, 2010 11:27 by magicrebirth
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>>> s '1/Mar/1215' >>> pattern = r"(\d+)" >>> re.match(pattern, s).groups() ('1',) >>> pattern = r"(\d+)/(Sept|Mar)/(\d+)" >>> re.match(pattern, s).groups() ('1', 'Mar', '1215')
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Python: simple REgex example
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regex
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Python