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Revision: 22631
at January 17, 2010 11:27 by magicrebirth
Initial Code 
>>> s
'1/Mar/1215'
>>> pattern = r"(\d+)"
>>> re.match(pattern, s).groups()
('1',)
>>> pattern = r"(\d+)/(Sept|Mar)/(\d+)"
>>> re.match(pattern, s).groups()
('1', 'Mar', '1215')
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Initial Title





Python: simple REgex  example









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regex









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Python