Revision: 2188
Updated Code
at January 12, 2007 08:06 by miziomon
Updated Code
Public Function CreateDatatable() as DataTable
' Create new datatable
Dim mydatatable As New DataTable
' Create columns
mydatatable.Columns.Add("field_a", Type.GetType("System.String"))
mydatatable.Columns.Add("field_b", Type.GetType("System.String"))
' Declare row
Dim myrow As DataRow
' create new row
myrow = mydatatable.NewRow
myrow("field_a") = "filed a row 1"
myrow("field_b") = "filed b row 1"
mydatatable.Rows.Add(myrow)
' create another row
myrow = mydatatable.NewRow
myrow("field_a") = "filed a row 2"
myrow("field_b") = "filed b row 3"
mydatatable.Rows.Add(myrow)
' return the datatable filled with 2 columns and rows
return mydatatable
End Sub
Revision: 2187
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at January 12, 2007 07:49 by miziomon
Initial Code
Private Sub datatablemanuale()
' creazione dati
Dim mydatatable_appointments As New DataTable
' creazione colonne con i dati
mydatatable_appointments.Columns.Add("orario", Type.GetType("System.String"))
mydatatable_appointments.Columns.Add("name", Type.GetType("System.String"))
mydatatable_appointments.Columns.Add("surname", Type.GetType("System.String"))
Dim myrow As DataRow
myrow = mydatatable_appointments.NewRow
myrow("orario") = "8.00"
myrow("name") = "maurizio"
myrow("surname") = "pelizzone"
mydatatable_appointments.Rows.Add(myrow)
myrow = mydatatable_appointments.NewRow
myrow("orario") = "9.00"
myrow("name") = "diego"
myrow("surname") = "grosso"
mydatatable_appointments.Rows.Add(myrow)
myrow = mydatatable_appointments.NewRow
myrow("orario") = "11.00"
myrow("name") = "dario"
myrow("surname") = "blengio"
mydatatable_appointments.Rows.Add(myrow)
End Sub
Initial URL
Initial Description
Howto create a new datatable manually
Initial Title
Create DataTable
Initial Tags
Initial Language
VB.NET