Revision: 11574
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at February 9, 2009 22:21 by rengber
Initial Code
public static Int32 GetInt32(byte[] buffer, int offset, EndianType byteOrder)
{
if (byteOrder == EndianType.LittleEndian)
{
return buffer[offset + 1] << 8 | buffer[offset];
}
else
{
return buffer[offset] << 8 | buffer[offset + 1];
}
}
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Found this in some code I've been maintaining/expanding. Quite clever.
Picture an array of bytes in binary
00000111 11100000 00000000 00000000
Now picture an Int32 in Binary
00000000000000000000000000000000
To grab a Little Endian Integer (16 bits) out of the array.
Take the second array element
11100000
Assign it to the Int32 variable
00000000000000000000000011100000
Bit shift it up by 8
00000000000000001110000000000000
Now OR it with the first Array element - could also just add.
<pre>
00000000000000001110000000000000
or 00000000000000000000000000000111
= 00000000000000001110000000000111
</pre>
Initial Title
Extracting an Int from a Little Endian or Big Endian Byte Array
Initial Tags
math
Initial Language
C#