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Posted By

kanuwadhwa on 03/19/11


Tagged

actionscript flash palindrome Flex


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Palindrome

 / Published in: ActionScript 3
 

Looking forward for the most optimized solution for the same

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  1. <?xml version="1.0" encoding="utf-8"?>
  2. <mx:Application xmlns:mx="http://www.adobe.com/2006/mxml" layout="absolute" creationComplete="init()">
  3. 	<mx:Script>
  4. 		<![CDATA[
  5. 			private var str:String = "abcba";
  6. 			public function init():void{
  7. 				var len:int = str.length;	
  8. 				for (var i:int = 0; i < len/2; i++) 
  9. 				{				
  10. 					var c1:String = str.charAt(i);
  11. 					var c2:String = str.charAt(len - i - 1); // 5-0-1 = 4, 5-1-1=3, 5-2-1 =2
  12. 					txt.text = "\n f1>> "+c1+ " >>>b1>> "+c2	
  13. 					if (c1 != c2)
  14. 					{ 
  15. 						txt.text += "\n false";
  16. 					}
  17. 					else 
  18. 					{
  19. 						txt.text += "\n true";
  20. 					}
  21. 				}
  22. 			}
  23. 		]]>
  24. 	</mx:Script>
  25. 	<mx:TextArea x="118" y="57" width="553" height="412" id="txt"/>
  26. </mx:Application>

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Posted By: ElntCor on March 19, 2011

This is not completely correct. You need to add a break, otherwise it shows true when only the character(s) in the middle are equal:

if (c1 != c2){ txt.text += "\n false"; break; }else{ txt.text += "\n true"; }

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