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Posted By

ekobudisetiyo on 07/10/06


Tagged

object open php5


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tylerhall
postNuKe
vaaaska


Open PHP5 Object, No need to declare variable name first

Published in: PHP 

I use this object verry often, so that I only need to pass one object as parameter on any function. No need to wory when we refactore the function Usage: $var = new open(); $var->url = 'http://www.world.com'; $var->title = 'Testing Site';

echo some_function($var);

Plain TextExpand 
  1. //PHP5 only//
  2.  
  3. class open
  4. {
  5.    var $____x = array();
  6.    function __construct($a = array())
  7.    {
  8.       $this->fromArray($a);
  9.    }
  10.  
  11.    function __set($name,$val)
  12.    {
  13.       $this->____x[$name] = $val;
  14.    }
  15.  
  16.    function __get($name)
  17.    {
  18.        if(isset($this->____x[$name])) return $this->____x[$name];
  19.    }
  20.  
  21.    function __isset($name)
  22.    {
  23.       return isset($this->____x[$name]);
  24.    }
  25.  
  26.    function toArray()
  27.    {
  28.       return $this->____x;
  29.    }
  30.  
  31.    function fromArray($a = array())
  32.    {
  33.       if(count($a)>0) foreach($a as $k => $v) $this->____x[$k] = $v;
  34.    }
  35.  
  36. }

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