Published in: SQL
SELECT DISTINCT pt_services.service_bezeichnungen, pt_class_services.class_services_name, count(*) AS total FROM service INNER JOIN pt_services ON service.id_pt_service = pt_services.id_pt_service INNER JOIN pt_class_services ON service.id_class_services = pt_class_services.id_class_services GROUP BY pt_services.id_pt_service, pt_class_services.id_class_services;
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