dsntos said on 26/Feb/2009

Thu, 26 Feb 2009 19:30:11 UTC

Or you can use this: $url= $_SERVER['HTTP_HOST'];

xtheonex said on 27/Feb/2009

Fri, 27 Feb 2009 02:48:54 UTC

Omg. How much of a retard do i feel now?! :P I Googled for an easy way of doing this and nothing came up so i created my own function, lol.

xtheonex said on 27/Feb/2009

Fri, 27 Feb 2009 02:51:57 UTC

Actually. No. That will only get the domain name of the host. My function, stips down any url passed to it. For eg. i used my function to standardize any urls submitted by users.

duniyadnd said on 27/Feb/2009

Fri, 27 Feb 2009 11:08:55 UTC

Did you just want to contain the domain's information without the subdomain www? Some site's use www. as a subdomain so you may want to include that. It's a good script, and pretty speedy, here's an alternative if you would prefer: function stripit ( $url ) { $url = trim($url); $url = preg_replace("/^(http:\/\/)*(www\.)*/is", "", $url); $url = preg_replace("/\/.*$/is" , "" ,$url); return $url; } Created a test for this and yours as well - btw, I just noticed that you have a problem for $url[3]. Don't know if you wanted to keep the sub-directory or not. $url[0] = " http://www.google.com/test "; $url[1] = "http://www.google.com/and"; $url[2] = "http://web.google.com/bla"; $url[3] = "http://google.com/go/"; $url[4] = "www.google.com/jeep"; $url[5] = "google.com/bam"; $url[6] = "http://google.com/forget"; $url[7] = "mail.google.com"; $url[8] = "google.co.in"; $url[9] = "http://google.co.uk"; $url[10] = "http://mail.google.co.uk"; $url[11] = "google.co.uk/"; $url[12] = "http://mail.google.co.uk/"; foreach ( $url as $u ) { echo $u.""; echo striptodomain($u).""; echo stripit($u).""; }

Comments on snippet: 'Strip URL to its domain name...'

dsntos said on 26/Feb/2009

xtheonex said on 27/Feb/2009

xtheonex said on 27/Feb/2009

duniyadnd said on 27/Feb/2009