# Problem 8

/ Published in: Java

Project Euler Problem 8:

"Find the greatest product of five consecutive digits in the 1000-digit number.

73167176531330624919225119674426574742355349194934 96983520312774506326239578318016984801869478851843 85861560789112949495459501737958331952853208805511 12540698747158523863050715693290963295227443043557 66896648950445244523161731856403098711121722383113 62229893423380308135336276614282806444486645238749 30358907296290491560440772390713810515859307960866 70172427121883998797908792274921901699720888093776 65727333001053367881220235421809751254540594752243 52584907711670556013604839586446706324415722155397 53697817977846174064955149290862569321978468622482 83972241375657056057490261407972968652414535100474 82166370484403199890008895243450658541227588666881 16427171479924442928230863465674813919123162824586 17866458359124566529476545682848912883142607690042 24219022671055626321111109370544217506941658960408 07198403850962455444362981230987879927244284909188 84580156166097919133875499200524063689912560717606 05886116467109405077541002256983155200055935729725 71636269561882670428252483600823257530420752963450"

Input: That huge number above.

Output: 40824

`public class Prob8{      public static void main(String[] argsv){         int[] a = init(argsv[0]);         int result = 0;         int maxsize = a.length - 4;         int product;         for(int i = 0; i < maxsize; i++){            product = a[i] * a[i + 1] * a[i + 2] * a[i + 3] * a[i + 4];            if(product > result){               result = product;            }         }         System.out.println(result);      }       private static int[] init(String str){         int[] result = new int[str.length()];         for(int i = 0; i < result.length; i++){            result[i] = new Integer(new Character(str.charAt(i)).toString()).intValue();         }         return result;      }   }`