# Problem 6

/ Published in: Java

Project Euler Question 6:

"The sum of the squares of the first ten natural numbers is,

1^2 + 2^2 + ... + 10^2 = 385 The square of the sum of the first ten natural numbers is,

(1 + 2 + ... + 10)^2 = 55^2 = 3025 Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is 3025 - 385 = 2640.

Find the difference between the sum of the squares of the first one hundred natural numbers and the square of the sum."

Input: 1 100

Output: 25164150

`public class Prob6{      public static void main(String[] argsv){         int start = new Integer(argsv[0]).intValue();         int end = new Integer(argsv[1]).intValue();         System.out.println(difference(start, end));      }       private static long difference(int start, int end){         return squareOfSum(start, end) - sumOfSquares(start, end);      }       private static long squareOfSum(int start, int end){         long result = 0;         while(start <= end){            result += start;            start++;         }         return result * result;      }    // Interval [start, end]      private static long sumOfSquares(int start, int end){         long result = 0;         while(start <= end){            result += start * start;            start++;         }         return result;      }   }`