We Recommend

Pro JavaScript Techniques Pro JavaScript Techniques
Pro JavaScript Techniques is the ultimate JavaScript book for the modern web developer. It provides everything you need to know about modern JavaScript, and shows what JavaScript can do for your web sites. This book doesn't waste any time looking at things you already know, like basic syntax and structures.


Posted By

Leech on 07/21/06


Tagged

images preloader


Versions (?)


Who likes this?

5 people have marked this snippet as a favorite

panatlantica
jkochis
visualAesthetic
shachi
vali29


Image Preloader v1.0


Published in: JavaScript 


URL: http://jsfromhell.com/classes/preloader

Image preloader with events and allows grouping the images to supply a synchronized loading. Created: 2005.08.13

  1. /*
  2. **************************************
  3. * Preloader Class v1.0 *
  4. * Autor: Carlos R. L. Rodrigues *
  5. **************************************
  6. */
  7. Preloader = function(){
  8. var o = this;
  9. o.img = []; o.r = []; o.g = [];
  10. o.n = {}; o.total = o.loaded = 0;
  11. };
  12. Preloader.prototype.add = function(i, g){
  13. var o = this, n = (o.g[o.total] = [g || "general"])[0];
  14. (g = o.n)[n] >= 0 ? ++g[n] : g[n] = 1;
  15. o.img[o.total++] = i;
  16. };
  17. Preloader.prototype.load = function(){
  18. var o = this, p = o.img, l = p.length, a, g = o.g;
  19. while(l--){
  20. (g[l][1] = a = new Image()).src = p[a.i = l];
  21. a.onload = function(){
  22. if(o.r[this.i]) return;
  23. !--o.n[g[this.i][(o.r[this.i] = 1) - 1]] && o.onGroupComplete && o.onGroupComplete(g[this.i][0]);
  24. o.onImageComplete && o.onImageComplete(this);
  25. (++o.loaded == o.total) && o.onComplete && o.onComplete();
  26. };
  27. (a.fileSize !== undefined ? a.fileSize > -1 : a.width) && a.onload();
  28. a.onerror = function(){
  29. o.onImageError && o.onImageError(this);
  30. }
  31. }
  32. };
  33. Preloader.prototype.getImagesByGroup = function(n){
  34. var g = this.g, i = [], p = 0, n = n || "general";
  35. for(var j = g.length; j; g[--j][0] == n && (i[p++] = g[j][1]));
  36. return i;
  37. };

Report this snippet 

You need to login to post a comment.