advanced code snippet search
andyhartleeds on 11/26/08
numericnumberparityoddevenfunction
11/26/08 11:07am
if ($i&1) { 3. { 4. echo "$i is odd"; 5. } 6. else 7. { 8. echo "$i is even"; 9. }
Report this snippet Tweet
if($i % 2 ==0) {odd} else {even}
echo ($i % 2 == 0) ? "odd" : "even";
What do I win?
Comment:
You need to login to post a comment.
if($i % 2 ==0) {odd} else {even}
echo ($i % 2 == 0) ? "odd" : "even";What do I win?