<?xml version="1.0" encoding="utf-8"?>
<rss version="2.0" xmlns:dc="http://purl.org/dc/elements/1.1/">
<channel>
<title>Snipplr - cahyadsn</title>
<link>http://snipplr.com/users/cahyadsn</link>
<description>Recent snippets posted on Snipplr.com</description>
<language>en-us</language>
<pubDate>Sun, 19 May 2013 13:59:55 GMT</pubDate>
<item>
<title>(MySQL) Pivot table Schedule</title>
<link>http://snipplr.com/view/66323/pivot-table-schedule/</link>
<description><![CDATA[ <p>You have a schedule table (period, day, subject, room) with a primary key period,day to avoid duplicate bookings. You wish to display the schedule as periods, subjects and rooms in rows, and days of the week in columns.</p> ]]></description>
<pubDate>Wed, 25 Jul 2012 13:43:46 GMT</pubDate>
<guid>http://snipplr.com/view/66323/pivot-table-schedule/</guid>
</item>
<item>
<title>(MySQL) Age in Years for Given Birthdate</title>
<link>http://snipplr.com/view/66321/age-in-years-for-given-birthdate/</link>
<description><![CDATA[ <p>Given a birthdate in @dob, here are two simple formulae for age in years :
(the second formulae is for age in years to two decimal places, ignoring day of month)</p> ]]></description>
<pubDate>Wed, 25 Jul 2012 13:31:22 GMT</pubDate>
<guid>http://snipplr.com/view/66321/age-in-years-for-given-birthdate/</guid>
</item>
</channel>
</rss>