Snipplr

(Scheme) Advanced Pi Approximation - NihilistDandy

Fri, 04 Feb 2011 17:21:10 GMT

Referencing the Machin-like formula in the linked reddit comment. Should be as exact as Scheme allows.

(Scheme) Shorter Pi Approximation - NihilistDandy

Thu, 03 Feb 2011 14:59:35 GMT

#72 at the URL

(Scheme) Pi Approximation in Scheme - NihilistDandy

Thu, 03 Feb 2011 14:44:34 GMT

Based on the pi approximation (100 - ((2125^3 + 214^3 + 30^3 + 37^2)/(82^5)))^(1/4), referenced in equation 57 at the referenced URL.

(Scheme) Function split list to lists of length n. - jcubic

Wed, 25 Aug 2010 03:44:16 GMT

Function group-for which return list of list of length n. (group-for '(1 2 3 4 5 6 7 8 9) 3) => ((1 2 3) (4 5 6) (7 8 9))

(Scheme) thi lth - darkbaron1912

Thu, 05 Aug 2010 16:15:11 GMT

(Scheme) thi lap trinh ham - darkbaron1912

Thu, 05 Aug 2010 00:43:02 GMT

(Scheme) scheme: replace a string - magicrebirth

Fri, 12 Feb 2010 01:23:07 GMT

Written for the impromptu-scheme environment.. other schemes might need different procedures..

(Scheme) list flatten - magicrebirth

Fri, 12 Feb 2010 01:22:00 GMT

(Scheme) Scheme: find a substring - magicrebirth

Tue, 09 Feb 2010 03:47:29 GMT

(Scheme) Change list in place : scheme/impromtu - magicrebirth

Thu, 04 Feb 2010 06:27:51 GMT

set-car! and set-cdr! change a list 'in-place'. But, if you like the pointer metaphore... you could use macro's instead of procedures... stupidly simple example...

(Scheme) evolutionOrgPerson+ mozillaAbPersonAlpha ldiff to openldap 2.4 - gpupo

Wed, 23 Dec 2009 08:35:32 GMT

Ldif for add evolutionOrgPerson and mozillaAbPersonAlpha schema to openldap 2.4 More about openldap 2.4: http://blog.gilmar.eti.br/solucao-para-o-bug-do-ubuntu-910-na-instalaca

(Scheme) scheme: check for optional arguments - magicrebirth

Sat, 12 Dec 2009 18:05:02 GMT

(Scheme) Interpreter for Lectures 15-16 - clementi

Wed, 11 Feb 2009 11:42:25 GMT

(Scheme) cons - ikfjwe

Tue, 14 Oct 2008 13:45:00 GMT

cons is not destructive.

(Scheme) Grouping keys of an associative list - jarnaldich

Wed, 30 Apr 2008 14:23:31 GMT

Given an an associative list ((k1 . v1) (k2 . v2) ... (kn . vn)), with possibly equal values for ki, it returns another alist where all cells have distinct keys and where values originally associated to the same key have been grouped as a list in the new cons cell. Ouch! This is much harder to explain than to code. Just check the commented example in the code.